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Sainik School Maths Approximation Question 6 to 10
6. 18.24 when multiplied by 20.0, we get the approximate result is
365
368
364
362
7. what approximate value should come in place of question mark(?)?
840.0003/23.999=?
47
8
35
18
8. what is the approximate value of (8531 + 6307 + 1093)÷ (501 + 724 + 396)?
a.10
b.7
c.16
d.13
9. Calculate the value (897 + 635 + 468 – 120 – 721) its nearest hundred.
110
1200
1300
1000
10. approximation value of (6.97 × 0.093) is
0.7
0.8
7.0
8.0

Sainik School Maths Approximation Question 1 to 5
1. 1372 ÷ 28 × x – 1653 = 748
49
13
15
18
2. What is the approximation value of 275.0003 × 3.005?
825
830
810
835
3. What is the approx. value of 16268?
16200
16300
16260
16270
4. The number 66.0684, correct to the nearest ten is
66.068
66.07
66.1
70
5. The nearest thousand of 29789 will be written as
29000
29700
29800
30000

Class 6 Math Olympiad Approximations Question 14
The sum of first 7 multiple of 13 is approximately
360
365
370
375

Class 6 Math Olympiad Approximations Question 16
A water tank had 37625 L of water. Of this 7648 L was used up, approximately what quantity of water (rounded of nearest tens) is left in the container now?
30000 L
29983 L
29980 L
29990 L

Class 6 Math Olympiad Approximations Question 15
248.251 ÷ 12.62 × 20.52 = ?
400
450
350
600

Class 6 Math Olympiad Approximations Question 13
Calculate the value 1524.79 × 19.92 + 495.26 to its nearest thousand
33000
34000
31000

Class 6 Math Olympiad Approximations Question 12
Calculate the value (897 + 635 + 468 – 120 – 721) its nearest hundred.
1100
1200
1300
1000

Class 6 Math Olympiad Approximations Question 11
What is the approximate value of (8531 + 6307 + 1093) ÷ (501 + 724 + 396)?
10
7
16
13

Class 6 Math Olympiad Approximations Question 10
Calculate the approximate value of expression. 6885.009 – 419.999 – 94.989
6370
6830
6200
6450

Class 6 Math Olympiad Approximations Question 9
On dividing 93.45 by 0.015, what is the approximate answer?
0.6
60
600
6000

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